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If \(f(x)=x^2-2x\) and \(g(x)=x-2\), what is the simplified form of \(\left(\frac{f}{g}\right)(x)\)?यदि \(f(x)=x^2-2x\) और \(g(x)=x-2\) हों, तो \(\left(\frac{f}{g}\right)(x)\) का सरल रूप क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x,\ x\neq 2\)\(x,\ x\neq 2\)
\(\frac{x^2-2x}{x-2}=\frac{x(x-2)}{x-2}=x\), but \(x\neq 2\). A cancelled factor does not remove the original restriction.\(\frac{x^2-2x}{x-2}=\frac{x(x-2)}{x-2}=x\), पर \(x\neq 2\)। cancelled factor से मूल restriction खत्म नहीं होती।
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