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If \(f(x)=x^2\) and \(g(x)=2x+1\), what is the value of \((f+g)(-1)\)?

Answer and explanation

Correct answer: 0

The sum of two functions is defined by \((f+g)(x)=f(x)+g(x)\). Here, \(f(-1)=(-1)^2=1\) and \(g(-1)=2(-1)+1=-1\), so \((f+g)(-1)=1+(-1)=0\). Option B is only the value of \(f(-1)\), not the sum. In an exam, evaluate both functions separately before adding them.

Related tags

Relations-FunctionsAlgebra-Real-FunctionsFunction-EvaluationAlgebra Of Real FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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