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If (f(x)=\sqrt{x+2}) and (g(x)=\frac{1}{x-1}), what is the real domain of ((f+g)(x))?यदि (f(x)=\sqrt{x+2}) और (g(x)=\frac{1}{x-1}) हों, तो ((f+g)(x)) का वास्तविक डोमेन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-2,\infty)-{1})([-2,\infty)-{1})
For (\sqrt{x+2}), (x\ge -2), and for (\frac{1}{x-1}), (x\ne 1). Apply both conditions together.(\sqrt{x+2}) के लिए (x\ge -2) और (\frac{1}{x-1}) के लिए (x\ne 1) चाहिए। दोनों शर्तों को साथ लगाएं।
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