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If \(f(x)=x+1\) and \(g(x)=x^2+1\), what is the domain of \(\left(\frac{g}{f}\right)(x)\)?यदि \(f(x)=x+1\) और \(g(x)=x^2+1\) हों, तो \(\left(\frac{g}{f}\right)(x)\) का डोमेन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\mathbb{R}-{-1}\)\(\mathbb{R}-{-1}\)
In \(\frac{g}{f}\), the denominator is \(f(x)=x+1\), so \(x=-1\) is excluded. Identify the denominator function carefully.\(\frac{g}{f}\) में हर \(f(x)=x+1\) है, इसलिए \(x=-1\) हटेगा। भागफल में हर वाले फलन को ध्यान से देखें।
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