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If \(f(x)=4\) and \(g(x)=x^2-1\), what is \((f-g)(x)\)?

Answer and explanation

Correct answer: \(5-x^2\)

By the definition of the difference of two functions, \((f-g)(x)=f(x)-g(x)\). Hence, \((f-g)(x)=4-(x^2-1)=4-x^2+1=5-x^2\). The brackets are important because the minus sign changes the signs inside \(g(x)\). Exam tip: in \(f-g\), subtract the second function from the first.

Related tags

Relations-And-FunctionsAlgebra-Of-Real-FunctionsFunction-DifferenceAlgebra Of Real FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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