If \(f(x)=x^2-1\) and \(g(x)=x+1\), what is the value of \(\left(\frac{f}{g}\right)(0)\)?

Correct answer: \(-1\)

For the quotient function, \(\left(\frac{f}{g}\right)(0)=\frac{f(0)}{g(0)}\). Here, \(f(0)=0^2-1=-1\) and \(g(0)=0+1=1\), so the value is \(\frac{-1}{1}=-1\). Option B is incorrect because it ignores the negative sign in the numerator. Exam tip: For a quotient of functions, evaluate the numerator and denominator separately and verify that the denominator is not zero.