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If \(f(x)=x^2-4\) and \(g(x)=x-2\), what is the simplified form of \(\left(\frac{f}{g}\right)(x)\), where (x\ne 2)?यदि \(f(x)=x^2-4\) और \(g(x)=x-2\) हों, तो \(\left(\frac{f}{g}\right)(x)\) का सरल रूप क्या है, जहाँ (x\ne 2)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x+2)(x+2)
\(\frac{x^2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2\), but (x\ne 2). Keep the original denominator restriction even after simplification.\(\frac{x^2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2\), पर (x\ne 2)। सरल करने के बाद भी मूल हर की शर्त याद रखें।
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