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If f(x)=4x^2-3 and g(x)=x^2+8, what is the value of (f-g)(x)?

Answer and explanation

Correct answer: 3x^2-11

The difference of two functions is defined as (f-g)(x)=f(x)-g(x). Thus, (f-g)(x)=(4x^2-3)-(x^2+8)=4x^2-3-x^2-8=3x^2-11. In option D, the coefficients of x^2 have been added instead of subtracted. Exam tip: When subtracting a function in parentheses, change the signs of all its terms.

Related tags

AlgebraReal FunctionsFunction SubtractionPolynomialsAlgebra Of Real FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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