0 reads0 ratings0 helpful
If \(f(x)=x^2+10\) and \(g(x)=x^2+4\), what is the value of \((f-g)(1)\)?यदि \(f(x)=x^2+10\) और \(g(x)=x^2+4\) हैं, तो \((f-g)(1)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 66
First, \(f(1)=1^2+10=11\) and \(g(1)=1^2+4=5\). Hence, \((f-g)(1)=f(1)-g(1)=11-5=6\). Equivalently, \(f(x)-g(x)=(x^2+10)-(x^2+4)=6\), since the \(x^2\) terms cancel. Exam tip: For \((f-g)(a)\), always calculate \(f(a)-g(a)\), not their sum.पहले \(f(1)=1^2+10=11\) और \(g(1)=1^2+4=5\) निकालते हैं। इसलिए \((f-g)(1)=f(1)-g(1)=11-5=6\)। सीधे \(f(x)-g(x)=(x^2+10)-(x^2+4)=6\) भी प्राप्त किया जा सकता है, क्योंकि \(x^2\) वाले पद कट जाते हैं। परीक्षा-युक्ति: \((f-g)(a)\) में हमेशा \(f(a)-g(a)\) करें, जोड़ नहीं।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
