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If (f(x)=0) and (g(x)=3x^2-2), what will ((fg)(x)) be?

Answer and explanation

Correct answer: (0)

The direct answer is option B: \((fg)(x)=0\). The product of two functions is defined pointwise: \((fg)(x)=f(x)g(x)\). Substitute the given values: \((fg)(x)=0\cdot(3x^2-2)=0\). This is true for every allowed \(x\). Option A is only \(g(x)\), not the product, because it forgets the factor \(f(x)=0\). Option B is correct because multiplying any expression by zero gives zero. Option C, \(3x^2\), drops the constant term and also ignores the zero factor. Option D, \(2\), is not the product and has no valid calculation leading to it. The zero function outputs zero everywhere, so multiplying by it makes the entire product the zero function. Exam cue: for a product of functions, multiply their outputs, not their names or formulas selectively.

Related tags

AlgebraReal FunctionsZero FunctionProduct

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