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A menu offers 5 types of snacks and 4 types of drinks. In how many ways can one snack and one drink be chosen?

Answer and explanation

Correct answer: 20

For each of the 5 snacks, any one of the 4 drinks can be selected. By the multiplication principle, the total number of ways is \(5 \times 4 = 20\). The value 9 results from addition, which is not appropriate for two successive independent choices. Exam tip: multiply the numbers of choices for independent selections made together.

Related tags

Permutations And CombinationsCounting PrincipleMultiplication RulePermutationsMathematicsClass 11 Mcq

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