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Which formula counts choosing a president, secretary and treasurer from 7 people?

Answer and explanation

Correct answer: ⁷P₃

The three offices are distinct, so assigning the same three people to different offices produces different outcomes. The president can be selected in 7 ways, the secretary in 6 remaining ways, and the treasurer in 5 remaining ways. Thus the total is 7 × 6 × 5 = ⁷P₃ = 7!/(7−3)! = 210. Option C is therefore correct. ⁷C₃ would count only an unordered group of three people and would treat every assignment as the same, which is unsuitable for named posts. The expression 7³ incorrectly allows repetition and does not enforce different people. The value 3! counts only arrangements of an already chosen group, not the complete selection from seven people.

Related tags

PermutationDistinct PostsOrdered SelectionPermutationsPermutations And CombinationsMathematicsClass 11 Mcq

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