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Class 11MathematicsPermutations and CombinationsPermutationsExpert
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In arrangements of the letters of (PERMUTE), how many have (P) and an (E) at the two ends?

Answer and explanation

Correct answer: (240)

Choose the end for (P) and (E) in (2) ways; the remaining (5) letters include (E) repeated twice, so there are (\frac{5!}{2!}) arrangements. Exam tip: divide for a repeated end-letter left inside.

Related tags

PermutationsWord ArrangementEnd PositionsClass 11Permutations And CombinationsMathematicsClass 11 Mcq
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