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Class 11MathematicsPermutations and CombinationsPermutationsExpert
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(5)-letter words are formed from (8) distinct letters. If two special letters must both be included and not adjacent, how many words are possible?

Answer and explanation

Correct answer: (2160)

Choose the other (3) letters from (6), then subtract adjacent special-pair arrangements (2!\times4!) from total (5!). Exam tip: handle inclusion and adjacency restrictions separately.

Related tags

PermutationsLettersNon AdjacentClass 11Permutations And CombinationsMathematicsClass 11 Mcq
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