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Class 11MathematicsPermutations and CombinationsPermutationsExpert
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Using digits (0,1,2,3,4,5,6,7,8) without repetition, how many (6)-digit numbers include both (0) and (8)?

Answer and explanation

Correct answer: (13440)

Choose the other (4) digits with (0) and (8) in (\binom{7}{4}) ways; for each selection subtract (5!) leading-zero cases from (6!). Exam tip: leading zero correction is mandatory.

Related tags

PermutationsDigitsZero RestrictionClass 11Permutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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  8. 8If \(\frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=24\), what is the value of \(n\)?
  9. 9What is the value of \(\frac{22!}{20!\cdot 2!}-\frac{21!}{20!}\)?
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