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Class 11MathematicsPermutations and CombinationsPermutationsExpert
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(6) distinct students are to be seated on (9) distinct chairs. If two special students sit on adjacent chairs, how many ways are possible?

Answer and explanation

Correct answer: (40320)

There are (8) adjacent chair pairs and (2!) orders for the two special students, then the remaining (4) students occupy (7) chairs in (^{7}P_{4}) ways. Exam tip: with distinct chairs, account for empty chairs too.

Related tags

PermutationsChairsAdjacent PositionsClass 11Permutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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  1. 1A menu offers 5 types of snacks and 4 types of drinks. In how many ways can one snack and one drink be chosen?
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  3. 3How many (3)-digit numbers can be formed from digits (1,3,5,7,9) without repetition?
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  5. 5Three distinct prizes are to be awarded to seven students. No student can receive more than one prize. How many ways are possible?
  6. 6If \(\frac{(n+5)!}{(n+3)!}=210\), what is the value of \(n\)?
  7. 7What is the value of \(\frac{21!}{19!\cdot2!}-\frac{18!}{16!\cdot2!}\)?
  8. 8If \(\frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=24\), what is the value of \(n\)?
  9. 9What is the value of \(\frac{22!}{20!\cdot 2!}-\frac{21!}{20!}\)?
  10. 10If (5) different books are arranged in a row, how many ways are possible?
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