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(8) distinct players are to stand in a row. If two special players must not be at the ends, how many arrangements are possible?

Answer and explanation

Correct answer: (30240)

Place the two special players in the (6) inner positions in (^{6}P_{2}) ways and arrange the remaining (6) players in (6!) ways. Exam tip: handle restricted positions first.

Related tags

PermutationsLinear ArrangementPosition RestrictionClass 11Permutations And CombinationsMathematicsClass 11 Mcq

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