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How many distinct arrangements are possible using all letters of the word (PROBABILITY)?शब्द (PROBABILITY) के अक्षरों की कुल अलग-अलग व्यवस्थाओं की संख्या कितनी है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (19958400)(19958400)
There are (11) letters, with (B) and (I) repeated twice, so the count is (\frac{11!}{2!,2!}). Exam tip: divide by the factorial of each repeated letter.कुल (11) अक्षर हैं और (B,I) दो-दो बार आते हैं, इसलिए संख्या (\frac{11!}{2!,2!}) है। परीक्षा में हर repeated letter के factorial से अलग-अलग भाग दें।
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