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Class 11MathematicsPermutations and CombinationsPermutationsExpert
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(6) people are seated around a circular table. If (A) and (B) do not sit together, how many arrangements are possible?

Answer and explanation

Correct answer: (72)

Total circular arrangements are ((6-1)!), and adjacent (A,B) arrangements are (2!\times4!). Exam tip: for not adjacent, subtract the adjacent case from total.

Related tags

PermutationsCircular ArrangementNot AdjacentClass 11Permutations And CombinationsMathematicsClass 11 Mcq
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  5. 5Three distinct prizes are to be awarded to seven students. No student can receive more than one prize. How many ways are possible?
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  7. 7What is the value of \(\frac{21!}{19!\cdot2!}-\frac{18!}{16!\cdot2!}\)?
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  9. 9What is the value of \(\frac{22!}{20!\cdot 2!}-\frac{21!}{20!}\)?
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