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(6) men and (4) women are seated in a row so that no two women sit together. How many arrangements are possible?(6) पुरुष और (4) महिलाएं पंक्ति में इस तरह बैठें कि कोई दो महिलाएं साथ न बैठें, तो व्यवस्थाओं की संख्या क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (604800)(604800)
Arrange (6) men in (6!) ways, then place (4) women in (^{7}P_{4}) of the (7) gaps. Exam tip: use the gaps method for non-adjacent placement.पहले (6) पुरुषों को (6!) तरीकों से बैठाएं, फिर (7) खाली स्थानों में (4) महिलाओं को (^{7}P_{4}) तरीकों से रखें। परीक्षा में अलग-अलग रखने के लिए gaps विधि लगाएं।
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