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Class 11MathematicsPermutations and CombinationsPermutationsExpert
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How many distinct arrangements can be formed using all letters of the word (ARRANGE)?

Answer and explanation

Correct answer: (1260)

There are (7) letters and (R) repeats twice, so the count is (\frac{7!}{2!}). Exam tip: divide by factorials of repeated letters.

Related tags

PermutationsWord ArrangementRepeated LettersClass 11Permutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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  3. 3How many (3)-digit numbers can be formed from digits (1,3,5,7,9) without repetition?
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  5. 5Three distinct prizes are to be awarded to seven students. No student can receive more than one prize. How many ways are possible?
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  7. 7What is the value of \(\frac{21!}{19!\cdot2!}-\frac{18!}{16!\cdot2!}\)?
  8. 8If \(\frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=24\), what is the value of \(n\)?
  9. 9What is the value of \(\frac{22!}{20!\cdot 2!}-\frac{21!}{20!}\)?
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