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How many (5)-digit numbers can be formed from digits (1,2,3,4,5,6,7,8) without repetition such that the digits are in increasing order?अंकों (1,2,3,4,5,6,7,8) से बिना पुनरावृत्ति के (5) अंकों की कितनी संख्याएँ बनेंगी जिनमें अंकों का क्रम बढ़ता हुआ हो?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (56)(56)
Any chosen set of (5) digits has only (1) increasing order, so the count is (8C5). If the order is fixed, count only selection.किसी भी चुने गए (5) अंकों का बढ़ता हुआ क्रम केवल (1) होता है, इसलिए संख्या (8C5) है। क्रम निश्चित हो तो केवल चयन गिनें।
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