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How many (4)-digit numbers can be formed from digits (2,3,4,5,6,7,8,9) without repetition and divisible by (25)?अंकों (2,3,4,5,6,7,8,9) से बिना पुनरावृत्ति के कितनी (4) अंकों की संख्याएँ बनेंगी जो (25) से विभाज्य हों?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (60)(60)
The last two digits can only be (25,75), and the first two places are filled in (6P2) ways. For divisibility by (25), fix the last two digits.अंतिम दो अंक केवल (25,75) हो सकते हैं और पहले दो स्थान (6P2) तरीकों से भरते हैं। (25) से विभाज्यता में अंतिम दो अंक तय करें।
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