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(5) boys and (4) girls are to be seated in a row so that no two girls sit together. How many arrangements are possible?

Answer and explanation

Correct answer: (17280)

Arrange boys in (5!) ways and place (4) girls in (6) gaps in (6P4) ways. The gap method is most useful here.

Related tags

PermutationsClass11ExpertNo AdjacentPermutations And CombinationsMathematicsClass 11 Mcq

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