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How many (4)-digit numbers can be formed from digits (1,2,3,4,5,6,7) without repetition that are divisible by (5)?अंकों (1,2,3,4,5,6,7) से बिना पुनरावृत्ति के (4) अंकों की कितनी संख्याएँ बनेंगी जो (5) से विभाज्य हों?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (120)(120)
The last digit must be (5), and the remaining (3) places have (6P3) arrangements. Apply divisibility conditions first.अंतिम अंक केवल (5) होगा और बाकी (3) स्थानों पर (6P3) व्यवस्थाएँ होंगी। विभाज्यता की शर्त पहले लगाएं।
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