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In arrangements of digits (1,2,3,4,5,6,7,8), how many have (2) and (4) not adjacent and (6) before (8)?अंकों (1,2,3,4,5,6,7,8) की व्यवस्थाओं में (2) और (4) साथ न हों तथा (6), (8) से पहले आए, ऐसी कितनी व्यवस्थाएं हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (15120)(15120)
First take total arrangements with (6) before (8), (8!/2), then subtract half of the block arrangements where (2,4) are adjacent. Separate order and non-adjacency conditions.पहले (6) पहले (8) वाली कुल (8!/2) व्यवस्थाएं लें, फिर (2,4) साथ वाली आधी खंड-व्यवस्थाएं घटाएं। क्रम और न-साथ की शर्त को अलग करें।
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