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How many (5)-digit odd numbers can be formed from digits (0,1,2,3,4,5,6,7,8,9) without repetition if exactly one of (2,4,6) is included?अंकों (0,1,2,3,4,5,6,7,8,9) से बिना पुनरावृत्ति कितनी (5)-अंकीय विषम संख्याएं बनेंगी जिनमें (2,4,6) में से ठीक एक अंक शामिल हो?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (6300)(6300)
First include exactly one digit from (2,4,6), then make cases for an odd unit digit. Handle oddness and compulsory choice together.पहले (2,4,6) में से ठीक एक अंक शामिल करें और अंतिम अंक विषम रखने के केस बनाएं। विषमता और अनिवार्य चयन को साथ संभालें।
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