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Class 11MathematicsPermutations and CombinationsPermutationsExpert
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A code has (3) letters followed by (3) digits. It uses (7) distinct letters without repetition and exactly one digit is repeated twice among (10) digits. How many codes are possible?

Answer and explanation

Correct answer: (56700)

The letter part has (^{7}P_3) ways, and in the digit part choose the repeated digit in (10) ways, the other digit in (9) ways and its position in (3) ways. Count code parts separately.

Related tags

PermutationsCodesRepetitionPermutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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