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In arrangements of (CALENDAR), how many distinct arrangements have the two (A)'s not together?शब्द (CALENDAR) की व्यवस्थाओं में दोनों (A) साथ न हों, ऐसी कितनी भिन्न व्यवस्थाएं हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (15120)(15120)
Subtract the adjacent (A) cases (7!) from the total (8!/2!). For non-adjacent identical letters, subtraction is simple.कुल (8!/2!) व्यवस्थाओं में से (A) साथ वाली (7!) व्यवस्थाएं घटाएं। समान अक्षरों के न-साथ प्रश्न में घटाने की विधि सरल है।
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