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In arrangements of digits (1,2,3,4,5,6,7,8,9), how many have (1) before (2) before (3), and (4) before (5)?अंकों (1,2,3,4,5,6,7,8,9) की व्यवस्थाओं में (1) पहले (2) से पहले (3) आए और (4) पहले (5) से आए, ऐसी कितनी व्यवस्थाएं हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (30240)(30240)
In the total (9!) arrangements, the (3!) orders of (1,2,3) and (2!) orders of (4,5) are equally likely. So use (9!/(3!2!)).कुल (9!) व्यवस्थाओं में (1,2,3) के (3!) और (4,5) के (2!) क्रम समान रूप से संभव हैं। इसलिए (9!/(3!2!)) लें।
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