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In arrangements of (A,B,C,D,E,F,G,H,I), how many have (A,B,C) consecutive but not in the order (A,B,C)?

Answer and explanation

Correct answer: (25200)

Treat the three letters as one block, giving (7!) arrangements, and inside it (3!-1) valid orders. Count the internal arrangements of the block separately.

Related tags

PermutationsBlock MethodLettersPermutations And CombinationsMathematicsClass 11 Mcq

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