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How many (5)-digit numbers can be formed from digits (0,1,2,3,4,5,6,7) without repetition if (0) is included and the number is divisible by (5)?अंकों (0,1,2,3,4,5,6,7) से बिना पुनरावृत्ति कितनी (5)-अंकीय संख्याएं बनेंगी जिनमें (0) शामिल हो और संख्या (5) से विभाज्य हो?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (1200)(1200)
The last digit is (0) or (5), and if (5) is last, (0) must be included inside. Count divisibility and compulsory digit cases separately.अंतिम अंक (0) या (5) होगा, और (5) अंत में होने पर (0) को भीतर शामिल करना होगा। विभाज्यता और अनिवार्य अंक को अलग केस में गिनें।
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