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What is the total number of distinct arrangements of the letters of (REPETITION)?शब्द (REPETITION) के अक्षरों की कुल भिन्न व्यवस्थाएं कितनी हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (453600)(453600)
Here (E,T,I) are each repeated twice, so the count is (10!/(2!2!2!)). Divide by the factorial of each repeated letter.इसमें (E,T,I) दो-दो बार हैं, इसलिए संख्या (10!/(2!2!2!)) है। हर दोहराए अक्षर के फैक्टोरियल से भाग दें।
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