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What is the total number of distinct arrangements of the letters of (PROBABILITY)?शब्द (PROBABILITY) के अक्षरों की कुल भिन्न व्यवस्थाएं कितनी हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (9979200)(9979200)
Here (B) and (I) are repeated twice, so the count is (11!/(2!2!)). Identifying repeated letters is the first step.इस शब्द में (B) और (I) दो-दो बार हैं, इसलिए संख्या (11!/(2!2!)) है। दोहराए अक्षर पहचानना पहला कदम है।
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