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How many (6)-digit odd numbers less than (400000) can be formed from digits (1,2,3,4,5,6,7,8,9) without repetition?अंकों (1,2,3,4,5,6,7,8,9) से बिना पुनरावृत्ति (400000) से छोटी कितनी (6)-अंकीय विषम संख्याएं बनेंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (10920)(10920)
The first digit must be (1,2,3), and the last digit must be odd, so cases are needed. Count the bound and oddness together.पहला अंक (1,2,3) होना चाहिए और अंतिम अंक विषम होना चाहिए, इसलिए केस बनते हैं। सीमा और विषमता दोनों को साथ गिनें।
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