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How many distinct arrangements can be formed from the letters of (CALCULUS)?शब्द (CALCULUS) की कितनी भिन्न व्यवस्थाएं बनेंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (10080)(10080)
There are (8) letters with (C,L,U) each repeated twice, so the count is (8!/(2!2!2!)). Identifying repetitions is the key step.(8) अक्षरों में (C,L,U) दो-दो बार हैं, इसलिए संख्या (8!/(2!2!2!)) है। आवृत्तियों को पहचानना मुख्य कदम है।
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