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How many (6)-digit numbers can be formed from (0,1,2,3,4,5,6,7,8,9) without repetition if the first digit is odd and the last digit is even?

Answer and explanation

Correct answer: (67200)

There are (5) odd choices for the first digit and (5) even choices for the last digit. The middle (4) places are filled from (8) digits in (^{8}P_4) ways, giving (5\cdot5\cdot1680=42000).

Related tags

PermutationsDigitsFirst Odd Last EvenPermutations And CombinationsMathematicsClass 11 Mcq

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