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Subjects
Class 11MathematicsPermutations and CombinationsPermutationsHard
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(9) distinct books are to be arranged in a row. Three particular books should not all be together as one block. How many arrangements are possible?

Answer and explanation

Correct answer: (322560)

Subtract cases where the three particular books are together, (7!\cdot3!), from total (9!). The answer is (362880-30240=332640).

Related tags

PermutationsBooksNot All TogetherPermutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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