0 reads0 ratings0 helpful
How many (5)-digit numbers can be formed from (1,2,3,4,5,6,7,8,9) without repetition, starting with (3) and even?अंकों (1,2,3,4,5,6,7,8,9) से बिना पुनरावृत्ति (5) अंकों की कितनी संख्याएं (3) से शुरू और सम होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (360)(360)
The first digit is fixed as (3), and the last place has (4) even choices. The middle (3) places are filled in (7\cdot6\cdot5) ways, giving (840).पहला अंक (3) निश्चित है और अंतिम स्थान के लिए (4) सम विकल्प हैं। बीच के (3) स्थान (7\cdot6\cdot5) तरीकों से भरेंगे, कुल (840) है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
