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How many (4)-digit numbers can be formed from (1,2,3,4,5,6,7,8) without repetition and containing both (2) and (3)?अंकों (1,2,3,4,5,6,7,8) से बिना पुनरावृत्ति (4) अंकों की कितनी संख्याएं बनेंगी जिनमें (2) और (3) दोनों शामिल हों?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (720)(720)
Choose the other (2) digits from (6) digits in (\binom{6}{2}) ways and arrange the (4) digits in (4!) ways. The total is (15\cdot24=360).बाकी (2) अंक (6) अंकों में से (\binom{6}{2}) तरीकों से चुनें और (4) अंकों को (4!) तरीकों से सजाएं। कुल (15\cdot24=360) है।
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