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A necklace is to be made with (8) distinct beads. If two particular beads remain together and flipping is considered the same, how many necklaces are possible?

Answer and explanation

Correct answer: (720)

Treat the two beads as one block, so the necklace count for (7) units is (\frac{(7-1)!}{2}), with (2!) internal ways. The total is (720).

Related tags

PermutationsNecklaceTogetherPermutations And CombinationsMathematicsClass 11 Mcq

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