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How many (5)-digit numbers greater than (50000) and odd can be formed from (1,2,3,4,5,6,7,8) without repetition?अंकों (1,2,3,4,5,6,7,8) से बिना पुनरावृत्ति (5) अंकों की कितनी संख्याएं (50000) से बड़ी और विषम होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (900)(900)
The first digit must be (5,6,7,8), and the last digit must be odd. Counting the cases gives (900) numbers.पहला अंक (5,6,7,8) होना चाहिए और अंतिम अंक विषम होना चाहिए। cases गिनने पर कुल (900) संख्याएं मिलती हैं।
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