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How many distinct arrangements are possible using the letters of (COMMITTEE)?शब्द (COMMITTEE) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (45360)(45360)
There are (9) letters with (M,T,E) each repeated twice, so (\frac{9!}{2!2!2!}=45360). In exams, put each repeated letter factorial in the denominator.(9) अक्षरों में (M,T,E) दो-दो बार हैं, इसलिए (\frac{9!}{2!2!2!}=45360)। परीक्षा में हर repeated letter का factorial हर में रखें।
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