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In how many ways can (7) distinct books be arranged on a shelf so that two particular books are neither together nor both at the ends?

Answer and explanation

Correct answer: (3720)

Subtract together cases (6!\cdot2!) and both-end cases (2!\cdot5!) from (7!). There is no overlap because both-end positions are not together, so the result is (5040-1440-240=3360).

Related tags

PermutationsBooksRestricted PositionsPermutations And CombinationsMathematicsClass 11 Mcq

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