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How many arrangements of the letters of (ARRANGE) are possible in which the two (R)'s are not together?शब्द (ARRANGE) के अक्षरों की कितनी व्यवस्थाएं होंगी जिनमें दोनों (R) साथ न आएं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (900)(900)
First arrange the non-(R) letters in (\frac{5!}{2!}=60) ways and place two (R)'s in (\binom{6}{2}) gaps. The total is (60\cdot15=900).पहले बिना (R) के अक्षरों की (\frac{5!}{2!}=60) व्यवस्थाएं बनती हैं और (6) gaps में दो (R) (\binom{6}{2}) तरीकों से रखे जाते हैं। कुल (60\cdot15=900) है।
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