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How many distinct arrangements are possible using the letters of (MATHEMATICS)?शब्द (MATHEMATICS) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (9979200)(9979200)
There are (11) letters with (M,A,T) each repeated twice, so (\frac{11!}{2!2!2!}=4989600). In exams, divide by factorials of all repeated letters.(11) अक्षरों में (M,A,T) दो-दो बार आते हैं, इसलिए (\frac{11!}{2!2!2!}=4989600)। परीक्षा में सभी repeated letters के factorial से भाग दें।
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