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In how many ways can (11) distinct coins be arranged in a row if one particular coin is at either end?

Answer and explanation

Correct answer: (7257600)

The particular coin has (2) end choices and the remaining (10) coins are arranged in (10!) ways. The total is (2\cdot10!=7257600).

Related tags

PermutationsEnd PositionCoinsPermutations And CombinationsMathematicsClass 11 Mcq

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