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(8) distinct coins are arranged in a row. If two particular coins should not occupy the two ends, how many arrangements are possible?(8) अलग-अलग सिक्कों को पंक्ति में रखा जाए। दो विशेष सिक्के दोनों सिरों पर न हों, तो व्यवस्थाएं कितनी होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (38880)(38880)
Subtract the cases where the two particular coins occupy the two ends, which are (2!\cdot6!), from total (8!). The answer is (40320-1440=38880).कुल (8!) में से दोनों विशेष सिक्कों के सिरों पर आने वाली (2!\cdot6!) व्यवस्थाएं घटाएं। उत्तर (40320-1440=38880) है।
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