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How many distinct arrangements are possible using the letters of (ALGEBRA)?शब्द (ALGEBRA) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (2520)(2520)
There are (7) letters with (A) repeated twice, so (\frac{7!}{2!}=2520). In exams, divide by repeated letters.(7) अक्षरों में (A) दो बार है, इसलिए (\frac{7!}{2!}=2520)। परीक्षा में repeated letters से भाग देना जरूरी है।
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