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In how many ways can (4) distinct mobiles and (3) distinct books be arranged in a row so that all mobiles stay together?

Answer and explanation

Correct answer: (576)

The condition says that the four distinct mobiles must appear consecutively. Treat those four mobiles as one large block. Along with the three separate books, this gives four objects to arrange. The mobiles are still distinct, so their internal order must also be counted.

The four objects can be arranged in \(4!\) ways. Inside the mobile block, the four mobiles can be arranged in \(4!\) ways. Hence the total is \(4!\times4!=24\times24=576\). Therefore, option A is correct. Counting only the block arrangements would miss the different orders of the mobiles.

Related tags

PermutationsBlock MethodObjects

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